Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
It's an isosceles triangle, so the angles at the base are congruent:
![m\anlge WXY=m\angle WZY](https://tex.z-dn.net/?f=m%5Canlge%20WXY%3Dm%5Cangle%20WZY)
The triangle XYW is a rectangular triangle.
We know that the sum of the measures of angles in a triangle is 180°.
Therefore we have the equation:
![m\angle YWZ+90^o+17^o=180^o\\\\m\angle YWZ+107^o=180^o\ \ \ |-107^o\\\\m\angle YWZ=73^o](https://tex.z-dn.net/?f=m%5Cangle%20YWZ%2B90%5Eo%2B17%5Eo%3D180%5Eo%5C%5C%5C%5Cm%5Cangle%20YWZ%2B107%5Eo%3D180%5Eo%5C%20%5C%20%5C%20%7C-107%5Eo%5C%5C%5C%5Cm%5Cangle%20YWZ%3D73%5Eo)
Answer: 73
N²+20n+100 = (n+10)(n+10)
Yes is it a perfect square trinomial
![▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪](https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%20%20%7B%5Chuge%5Cmathfrak%7BAnswer%7D%7D%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA)
The equivalent expression is ~
![\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cboxed%7B%20%5Cmathfrak%7BStep%5C%3A%5C%3A%20By%5C%3A%5C%3AStep%5C%3A%5C%3AExplanation%7D%7D)
Let's evaluate f(b - 2) ~
1.Not Even
2.Even
3.Not Even
4.Not Even