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liq [111]
2 years ago
9

Prove: The opposite sides of a parallelogram are equal.

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
4 0
You either find the gradient or distance and if there are equal, therefore the opp are equal
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Y varies directly as x, if y = 8 , when x=4, find y when x =48
kaheart [24]

Answer:

y = 24

Step-by-step explanation:

8 : 4 : : y : 48

8 / 4 = y / 48

1 / 2 = y / 48

y = 48 / 2

y = 24

5 0
2 years ago
Read 2 more answers
Evaluate (x + y ) 0 for x = –3 and y = 5.
zubka84 [21]
(x+y)0
(-3+5)0
(-15)0
THE ANSWER IS 0 BECAUSE YOU ARE MULTIPLYING BY 0
6 0
3 years ago
Read 2 more answers
The polynomial is missing the coefficient of the third and last terms.
bulgar [2K]

In order to divide polynomials using synthetic division, you must be dividing by a linear expression and the leading coefficient (first number) must be a 1. For example, you can use synthetic division to divide by x + 3 or x – 6, but you cannot use synthetic division to divide by x2 + 2 or 3x2 – x + 7. If the leading coefficient is not a 1, then you must divide by the leading coefficient to turn the leading coefficient into a 1. For example, 3x – 1 would becomex minus 1/3 and 2x + 7 would becomex plus 7/2. If synthetic division will not work, then you must use long division.

8 0
2 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)
Usimov [2.4K]

Answer:

<em>71.6 degrees </em>

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

u.v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+(-9)²

|v| = √81+81

|v| = √162

36 = √80*√162 cos theta

36 = √12960 cos theta

36 = 113.84 cos theta

cos theta = 36/113.84

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

7 0
3 years ago
Read 2 more answers
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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