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Zolol [24]
3 years ago
5

How can you quickly calculate 20 percent of any bill amount?

Mathematics
2 answers:
Olin [163]3 years ago
8 0
Turn 20 into 20/60 then divide them
It equals 3
3%
inna [77]3 years ago
6 0
Take it and divide it by 5, or you can multiply it by .2
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Write the equivalent division statement to 32 × 1 4
sleet_krkn [62]

Answer:

448/32=14

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Stuart pays back two student loans over a 4-yr period. One loan charges the equivalent of 3% simple interest and the other charg
Ugo [173]

Answer:

The first loan L1 = $20,000

This is the loan with 3% simple interest

The second loan L2 = $4,000

This is the loan with 5.5% simple interest

Step-by-step explanation:

L1 + L2 = $24,000 ...(1)

4(3% of L1) + 4(5.5% of L2) = $3,280 ...(2)

Where the first term in equation (2) represents the total interest paid on loan 1 after 4 years

The second term represents total interest accruing to loan 2 after 4 years

From equation (1), we single out L1

L1 = 24,000 - L2

Substitute this value for L1 in equation (2)

288,000 + 10L2 = 328,000

L2 = $4,000

L1 = $24,000 - $4,000 = $20,000

5 0
4 years ago
Read 2 more answers
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
The circumference of a circle is 20π cm. What is the DIAMETER of the circle?
marshall27 [118]
D≈6.37

<span>CCircumference 20</span>
5 0
3 years ago
Read 2 more answers
If f(x) varies directly with x2, and f(x) = 96 when x = 4, find the value of f(2).
Scilla [17]
F ( x ) = k * x²
f ( 4 ) = 96
96 = k * 4²
96 = 16 k
k = 96 : 16
k = 6
f ( 2 ) = 6 * 2² = 6 * 4 = 24
Answer: D ) 24
6 0
3 years ago
Read 2 more answers
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