Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
a. 2 x 100 0 x 1 0 x 1/10 6 1/100b. 2 x 100 0 x 1 0 x 1/100 6 1/1000
Hope it helps! :D
Btw, where is B?
Answer:
1/4
Step-by-step explanation:
Answer:
47°
Step-by-step explanation:
Given that m<NLO = 41°, and m<NLM = 88°, according to angle addition postulate, m<OLM + m<NLO = m<NLM
Therefore, subtracting m<NLO from both sides will give us:
m<OLM = m<NLM - m<NLO
m<OLM = 88° - 41°
m<OLM = 47°
Answer:i got 329
Step-by-step explanation:
