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3 years ago

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ماسسعمسعمعميعمسعمسهجسهجس7جسهجيجههجرهجسعحسعحسعحسعحسهحس

1 answer:

In-s [12.5K]3 years ago

4 0

Answer you have to be more clear because i cant read that

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Some book are to be shared between 2 schools A and B in the ratio of 4:7 if school B received 90 books more than school A, calcu

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Answer:

it is very easy so focus

Step-by-step explanation:

$\frac{a}{b} = \frac{4}{7}$

b is more than a by 90

$\frac{a}{a + 90} = \frac{4}{7}$

$7a = 4a + 360$

$3a = 360$

$a = 120$

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Paul, Maria, Stephanie, and Andy have a total of $56 to spend at the amusement park. Admission will cost them $5 each for a tota

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A rectangular prism has a length of 12 in., a width of 5 in., and a height of 414 in.

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Answer:

16320 cubes are needed to fill the rectangular prism.

Step-by-step explanation:

Given : A rectangular prism has a length of 12 in., a width of 5 in., and a height of $4\frac{1}{4}$ in.

The prism is filled with cubes that have edge lengths of $\frac{1}{4}$ in.

To find : How many cubes are needed to fill the rectangular prism?

Solution :

A rectangular prism has

Length of 12 in.

Width of 5 in.

Height of $4\frac{1}{4}=\frac{17}{4}$ in.

Volume of rectangular prism is $V=L\times B\times H$

$V=12\times 5\times \frac{17}{4}$

$V=255 in^3$

A cube has length of $\frac{1}{4}$ in.

Volume of cube is $V=L^3$

$V=\frac{1}{4}^3$

$V=\frac{1}{64}in^3$

Cubes are needed to fill the rectangular prism is

$=\frac{\text{Volume of rectangular prism}}{\text{Volume of cubes}}$

$=\frac{255}{\frac{1}{64}}$

$=255\times 64$

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Therefore, 16320 cubes are needed to fill the rectangular prism.

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3 years ago

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Calcula para la razón trigonométrica considerando la razón correspondiente del ángulo opuesto:Sen (-45º)

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Answer:

$sen(-45^{o})-\frac{\sqrt{2}}{2}$

Step-by-step explanation:

Para resolver este problea podemos comenzar con las identidades pares e impares, las cuales nos dicen que:

sen(-u)=-sen(u)

por lo que podemos reescribir nuestro problema como:

sen(-45°)=-sen(45°)

Luego podemos tomar los triángulos comunes (ver imagen adjunta).

y calcular la razón de seno en donde:

$sen \theta = \frac{opuesto}{hipotenusa}$

para obtener:

$sen(-45^{o})=-\frac{1}{\sqrt{2}}$

ahora podemos racionalizar la fracción para obtener:

$sen(-45^{o})=-\frac{1}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}$

$sen(-45^{o})=-\frac{\sqrt{2}}{2}$

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15/18

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