The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
Answer:
Company A: 250+10n
Company B: 90+12n
Step-by-step explanation:
I have no problem answering but it wont let me open the pdf. I will gladly give you your points back just thought that you should know
Answer:
7
Step-by-step explanation:
280=40t/40
t=7
