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sergiy2304 [10]

3 years ago

12

Mark is building a custom wooden frame around his flower bed. The length of the frame is 5.45 feet, and the width of the frame i

s 3.275 feet.
What is the area of the flower bed without rounding?__ square feet

1 answer:

dedylja [7]3 years ago

8 0

Answer:

17.84875

Step-by-step explanation:

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Como resolver logaritmos avanzados

Firlakuza [10]

Answer:

could u put this in english

5 0

3 years ago

A cube has a surface area of 486 square meters. What is the volume of the cube.

Oksana_A [137]

V= s^3
a=486/6=81
s=sqrt(81)=9
v=9^3=729
the volume of the cube is 729cm^3

8 0

3 years ago

Read 2 more answers

Shawna, Ryan, and Dominic ate a whole pizza. Shawna ate 1

mafiozo [28]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

You need to add the amount Shawna & Ryan ate together, then subtract it from 1 to find the amount of pizza that was left for Dominic to eat.

$\frac{1}{3}$ + $\frac{1}{2}$ = ?

Make all the denominators the same to add fractions.

$\frac{1}{3}$ is $\frac{2}{6}$

$\frac{1}{2}$ is $\frac{3}{6}$

$\frac{2}{6}$ + $\frac{3}{6}$ = $\frac{5}{6}$

1 - $\frac{5}{6}$ = $\frac{1}{6}$

4 0

2 years ago

Tara is trying to solve the following equation 4.5x-4=14

Romashka-Z-Leto [24]

Answer:

$4.5x - 4 = 14 \\ 4.5x = 14 + 4 \\ 4.5x = 18 \\ x = \frac{18}{4.5} \\ x = 4$

8 0

2 years ago

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Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

$y_1$ is not a solution of the differential equation

$y_2$ is not a solution of the differential equation

$y_3$ is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is $y'' + y' = cos2x$

Let consider the first equation to substitute

$y_1 = cosx +sinx$

$y_1' = -sinx +cosx$

$y_1'' = -cosx -sinx$

So

$y_1'' - y_1' = -cosx -sinx -sinx +cosx$

$y_1'' + y_1' = -2sinx$

So

$-2sinx \ne cos2x$

This means that $y_1$ is not a solution of the differential equation

Let consider the second equation to substitute

$y_2 = cos2x$

$y_2' = -2sin2x$

$y_2'' = -4cos2x$

So

$y_2'' + y_2' = -4cos2x-2sin2x$

So

$-4cos2x-2sin2x \ne cos2x$

This means that $y_2$ is not a solution of the differential equation

Let consider the third equation to substitute

$y_3 = sin 2x$

$y_3' = 2cos 2x$

$y_3'' = -4sin2x$

So

$y_3'' + y_3' = -4sin2x - 2cos2x$

So

$-4sin2x - 2cos2x \ne cos2x$

This means that $y_3$ is not a solution of the differential equation

6 0

3 years ago