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2 years ago

Consider a sequence given by the formula f(n)=3n-1 starting with n=1. Generate the first 5 terms of the sequence

Mathematics

1 answer:

Rufina [12.5K]2 years ago

5 0

Answer:

The first 5 terms are 2, 5, 8, 11, 14.

Step-by-step explanation:

You use the formula to find out each term.
f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
Now to find each term:

n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14

So the first 5 terms are 2,5,8,11,14

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A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =

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3 years ago

In the diagram, BC¯¯¯¯¯∥DE¯¯¯¯¯ .<br><br> What is AE ?

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So there are two triangles here: Smaller one (ADE) and bigger one (ABC) and they both are similar.

So you can use proportions here.

AB / AC = AD / AE

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AD = 6

So plug in these values:

AB / AC = AD / AE becomes
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Find the function value. tan495°

inysia [295]

Answer: -1

Step-by-step explanation:

You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°

Tangent is equal to $\frac{sin(theta)}{cos(theta)}$ , we already solved theta which was 135°

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$sin135=\frac{\sqrt{2} }{2}$

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

$cos135=-\frac{\sqrt{2} }{2}$

The final step is to divide them. They are both fractions so you should multiply by the reciprocal.

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3 years ago

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