50 POINTS! QUICKLY Are the pairs of variables x and y the solutions to the equation x^2–2y=7?
2 answers:
Hi there!
We are given the equation:
x² - 2y = 7
To verify if each ordered pair is apart of the function, we can plug in their respective x and y values:
1. (5)² - 2(8) = 7
25 - 16 = 9 ≠ 7. This is NOT correct.
2. (-1)² - 2(-3) = 7
1 + 6 = 7. This is correct.
3. (-4)² - 2(-11.5) = 7
16 + 23 = 39 ≠ 7. This is NOT correct.
4. (1.2)² - 2(-2.78) = 7
1.44 +5.56 = 7. This is correct.
Thus, only 1 and 4 are the correct answers.
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Answer:
The expected value of rolling a 5 or 6 is 10.
Step-by-step explanation:
The sample space of rolling a standard number cube is:
S = {1, 2, 3, 4, 5 and 6}
The cube is standard, this implies that each side has an equal probability of landing face-up.
So, the probability of all the six outcomes is same, i.e. .
Now it is provided that Apu rolls the cube <em>n</em> = 30 times.
Let the random variable <em>X</em> represent the value on the face of cube.
The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.
So, P (X = 5 and X = 6) = 0.
Compute the probability of getting a 5 or 6 as follows:
P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)
= P (X = 5) + P (X = 6)
Compute the expected value of rolling a 5 or 6 as follows:
Thus, the expected value of rolling a 5 or 6 is 10.