I would love to use substitution (It is simplier that way I guess)
solve your system of equations.
x+2y=−1;x−y=5
Solve x+2y=−1 for x:
x+2y+−2y=−1+−2y(Add -2y to both sides)
x=−2y−1
Substitute (−2y−1) for x in x−y=5:
x−y=5
−2y−1−y=5
−3y−1=5(Simplify both sides of the equation)
−3y−1+1=5+1(Add 1 to both sides)
−3y=6
−3y/−3 = 6/−3(Divide both sides by -3)
y=−2
Substitute (−2) for y in x=−2y−1:
x=−2y−1
x=(−2)(−2)−1
x=3(Simplify both sides of the equation)
So the answer is (x = 3 and y = -2)
Using a system of equations, it is found that 225 adult tickets were sold for the school play.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable x: Number of adult tickets.
- Variable y: Number of student tickets.
A total of 376 tickets were sold for the school play, hence:
x + y = 376 -> y = 376 - x.
There were 74 fewer students tickets sold than adult tickets, hence:
y = x - 74.
Then:
x - 74 = 376 - x
2x = 450
x = 450/2
x = 225.
More can be learned about a system of equations at brainly.com/question/24342899
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