Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
Sorry what is the question I cannot see the question
I cant answer if i dont know what math would you mind telling me what math
Answer:
The solution is (0, 3/4)
Step-by-step explanation:
Please copy and share the instructions. Here they are: Solve the following system of linear equations.
Both of the equations can be reduced (simplified):
2x+8y = 6 => x + 4y = 3
15x + 20y = 15 => 3x + 4y = 3
Let's use the elimination by addition and subtraction method. Multiply the first equation by -1, obtaining
-x - 4y = -3
Add the second 3x + 4y = 3
equation to the
first.
We get: 2x = 0.
Thus, x = 0. Substituting 0 for x in the 1st original equation yields:
2(0) + 8y = 6. Then y = 6/8, or y = 3/4.
The solution is (0, 3/4).
Answer:
they are all equal side so add them up
Step-by-step explanation:
