Answer:
The coordinates of A would be (-1, 2)
Step-by-step explanation:
In order to find this, use the mid-point formula.
(xA + xB)/2 = xM
In this, the xA is the x value of point A, xB is the x value of point B, and xM is the x value of M. Now we plug in the known information and solve for xA.
(xA + 5)/2 = 2
xA + 5 = 4
xA = -1
Now we can do the same using the midpoint formula and the y values.
(yA + yB)/2 = yM
(yA + 10)/2 = 6
yA + 10 = 12
yA = 2
This gives us the midpoint of (-1, 2)
Answer:
Mike is not correct.
Step-by-step explanation:
The probability is an "out of" statement. meaning out of all 6 marbles if 2 are red how what is the probability of choosing a red marble the answer is 2 out of 6 or 1/3 or 0.3333333etc. For green the probability is 1 out of 6 or 1/6 or 0.16666666etc
Answer:
-4x-6x=-20=
x=2
-3(2x-3)=33=
x=-4
4x+3x+2x=180
x=20
Step-by-step explanation:
-4x-6x=-20
-4+(-6)=-10x
-10x=20 (divide both by 10)
x=-2 (divide by -1 to get positive)
x=2
-3(2x-3)=33
-6x+9=33
-9 . -9
-6x=24 (divide both by -6)
x=-4 (divide by -1 to make positive)
4x+3x+2x=180
(combine like terms)
9x=180 (divide both sides by 9)
x=20
For this case we must find the product of the following expression:
![\sqrt {12} * \sqrt {18}](https://tex.z-dn.net/?f=%5Csqrt%20%7B12%7D%20%2A%20%5Csqrt%20%7B18%7D)
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So, we have:
![\sqrt {12 * 18} =\\\sqrt {216} =](https://tex.z-dn.net/?f=%5Csqrt%20%7B12%20%2A%2018%7D%20%3D%5C%5C%5Csqrt%20%7B216%7D%20%3D)
We rewrite the 216 as![6 * 6 * 6 = 6 ^ 3 = 6 ^ 2 * 6](https://tex.z-dn.net/?f=6%20%2A%206%20%2A%206%20%3D%206%20%5E%203%20%3D%206%20%5E%202%20%2A%206)
![\sqrt {6 ^ 2 * 6} =](https://tex.z-dn.net/?f=%5Csqrt%20%7B6%20%5E%202%20%2A%206%7D%20%3D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20n%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bn%7D%20%7Bn%7D%7D%20%3D%20a)
Then, the expression is:
![6 \sqrt {6}](https://tex.z-dn.net/?f=6%20%5Csqrt%20%7B6%7D)
Answer:
Option D