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olga2289 [7]
3 years ago
15

Determine the modulus of each of the complex numbers in the matching pairs. List these moduli in order from smallest to largest.

Use the letters of the matching pair in your listing.
Suppose m = 2 + 6i, and |m + n| = 3√10 , where n is a complex number.

a. What is the minimum value of the modulus of n?

√10

Provide one example of the complex number, n.



A = J → 2 + 6i

B = F →75

C = H → -3 - i

D = I → 1 + i

E = G → 5 + 5i

these are my matching pairs
Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

the modulus of a complex number z = a + bi is:

Izl= √(a²+b²)

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a + bi

Im + nl = 3√10

√(a² + b²+ 2²+ 6²)= 3√10

√(a^2 + b^2 + 40) = 3√10

squaring both side

a²+b²+40 = 3^2*10 = 9*10 =90

a²+b²= 90 - 40

a²+b²=50

So,

|n|=√(a^2 + b^2) = √50

The modulus of n must be equal to the square root of 50.

now

values a and b such

a^2 + b^2 = 50.

for example, a = 5 and b = 5

5²+5²=25+25= 50

Then a possible value for n is:

n = 5+5i

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Sergeu [11.5K]

Answer:

<h2>x =  -  \frac{17}{4}</h2>

Step-by-step explanation:

6x + 3(4x - 2) = 5(2x - 8)

Expand the terms in the bracket and simplify

That's

6x + 12x  - 6 = 10x - 40 \\ 18x - 6 = 10x - 40

Using the subtraction property subtract 10x from both sides of the equation

18x - 10x - 6 = 10x - 10x - 40 \\ 8x - 6 =  - 40

<u>Add 6 to both sides of the equation</u>

8x + 6 - 6 =  - 40 + 6 \\ 8x =  - 34

<u>Divide both sides by 8</u>

\frac{8x}{8}  =  -  \frac{34}{8}

<u>Reduce the fraction with 2</u>

We have the final answer as

x =  -  \frac{17}{4}

Hope this helps you

7 0
3 years ago
Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
cluponka [151]

Under the given transformation, the Jacobian and its determinant are

\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2

so that

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv

where D' is the region D transformed into the u-v plane. The remaining integral is the twice the area of D'.

Now, the integral over D is

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y

but through the given transformation, the boundary of D' is the set of equations,

\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}

We require that u>0, and the last equation tells us that we would also need v>0. This means 1\le v\le\sqrt2 and 0, so that the integral over D' is

\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6

4 0
2 years ago
If a printer prints 28 copies in 1 minute how many would it print in 3 minutes and 45 seconds?
Wittaler [7]

3minutes 45 seconds = 3 45/60 = 3.75 minutes

28 copies/ 1 minute = x copies/3.75 minutes

using cross products

28 * 3.75 = 1 * x

105 = x

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3 0
3 years ago
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Bad White [126]
The answer would be 33
6 0
3 years ago
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Which linear equation has no solution?
attashe74 [19]

9514 1404 393

Answer:

  5x + 12 = 5x - 7

Step-by-step explanation:

There will be no solution when the coefficients of x are the same on both sides of the equal sign and the constants are different. That is the case for ...

  5x + 12 = 5x - 7

This reduces to ...

  19 = 0 . . . . . no value of x will make this be true: NO SOLUTION

3 0
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