9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
B. AC/EA = AB/DA because theyre equal slopes just different sizes
<span>Absolute value of -98 is 98
Hope I helped:D </span>
Answer:
72.00$
Step-by-step explanation:
25% = .25
.25 × 96.00 = 24
96 - 24 = 72
Point slope form of a line:

where

is your slope and

is a point on your line.
For a line with a slope of 3/5 that passes through (10, -2)...

Let's plug these values into our formula.

Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.

There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.