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stepladder [879]
2 years ago
5

A motorist travels 122 km before his first stop. If he had 10% of his journey to complete at this point, how long was the total

ride
Mathematics
1 answer:
dimaraw [331]2 years ago
5 0

Answer:

233km

Step-by-step explanation:

You might be interested in
PLEASE ANSWER ASAP!!!!! DONT NEED much explanation How many solutions does this system have? (photo below)
Tema [17]

Answer:

infinite solutions

Step-by-step explanation:

Multiply the first equation by 2

2(3x-5y) = 2*15

6x - 10y = 30

This is the same as the second equation

They are the same line

This means there are infinite solutions

3 0
4 years ago
40 is what percent of 32
Jobisdone [24]
40 = x% of 32

32x = 40
x = 40/32
x = 1.25

multiply by 100 to convert to percentage...

x = 125%

40 is 125% of 32
8 0
3 years ago
Read 2 more answers
John is building a fence around his home currently his fence measures 14 feet on each side but he wants to increase only the wid
nalin [4]

Answer:

The dimensions of rectangular fence are 14 feet and 20 feet.

Step-by-step explanation:

We are given the following in the question:

Length of rectangular fence = 14 feet

Width of fence = (14+x) feet

Area of rectangular field = 280 square feet

Area of rectangular field =

A= \text{Length}\times \text{Width}

Putting the values, we get,

280 = 14(14+x)\\\\14 + x = \dfrac{280}{14}\\\\14 + x = 20\\x =20-14\\x = 6

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.

7 0
3 years ago
Lonna had 30 minutes to do a three-problem quiz. She spent 11 minutes on question A and 4
STatiana [176]

Answer:

She had 15 minutes left.

Step-by-step explanation:

30 - 11 = 19

19 - 4 = <em>15</em>

8 0
3 years ago
Read 2 more answers
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

\log_{10} 7= 0.8451

\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

\log_{10}(147) = \log_{10}(7 * 7 * 3)

Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
3 years ago
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