All categories

3 years ago

You have 54 pictures to put in a photograph album.

Mathematics

1 answer:

tigry1 [53]3 years ago

3 0

It should be 13 I hope this is correct for you

You might be interested in

7. Which of these is equivalent to the expression 8+8+8+8+12?

LenKa [72]

Answer:

Step-by-step explanation:

There are four 8s, so s should represent one 8.

The 12 is made up of 4 * 3, so B should be the answer.

Answer: B or 4(s + 3)

When the brackets are removed, you get 4s + 12

4 0

2 years ago

Express the improper fraction as a mixed number in simplest form. 39/8

Vilka [71]

mixed number: 4 7/8 simplest form: (THERE IS NONE)

8 0

3 years ago

The vertex of this parabola is at (-2,-3). When the y-value is -2, the x-value is -5. What is the coefficient of the squared ter

ra1l [238]

Answer:

The coefficient of the squared term of the equation is 1/9.

Step-by-step explanation:

We are given that the vertex of the parabola is at (-2, -3). We also know that when the y-value is -2, the x-value is -5. Using this information we want to find the cofficient of the squared term in the parabola's equation.

Since we are given the vertex, we can use the vertex form:

$\displaystyle y=a(x-h)^2+k$

Where a is the leading coefficient and (h, k) is the vertex.

Since the vertex is (-2, -3), h = -2 and k = -3:

$\displaystyle y=a(x-(-2))^2+(-3)$

Simplify:

$y=a(x+2)^2-3$

We are also given that y = -2 when x = -5. Substitute:

$(-2)=a(-5+2)^2-3$

Solve for a. Simplify:

$\displaystyle \begin{aligned} -2&=a(-3)^2-3\\ 1&=9a \\a&=\frac{1}{9}\end{aligned}$

Therefore, our full vertex equation is:

$\displaystyle y=\frac{1}{9}(x+2)^2-3$

We can expand:

$\displaystyle y=\frac{1}{9}(x^2+4x+4)-3$

Simplify:

$\displaystyle y=\frac{1}{9}x^2+\frac{4}{9}x-\frac{23}{9}$

The coefficient of the squared term of the equation is 1/9.

3 0

3 years ago

Jamie throws a ball into the air with an initial upward velocity of 68 feet per second from a height of 12 feet. Write a quadrat

PtichkaEL [24]

Answer:

$h(t)=68t+12$

Step-by-step explanation:

let t= time in seconds, h=height in ft

height at $t_0=12ft$ = $h_o$

Velocity,v= $68m/s$

Height= $velocity*time=vt$

$h_t=h_0+h_(t-0)$

Therefore height after $t_n$ is obtained by adding height gained to initial height.

$h(t)=68t+12$

3 0

4 years ago

Verifying Properties of logarithms In Exercise,use a graphing utility to verify that the functions are equivalent for x > 0.

Ede4ka [16]

Answer:

Applying Quotient and power rule. Graphically, for x>0 both curves coincide.

Step-by-step explanation:

1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:

$lnx=log_{e}x\\\\f(x) = ln({\frac{x^{2}}{4}})\Rightarrow f(x)=ln{x^2}-ln4\Rightarrow f(x)=2lnx-ln4\\g(x) = 2 ln x - ln 4$

2) Check the graph below to see this equivalence. to see x>0 they both coincide.

7 0

3 years ago