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Lemur [1.5K]
3 years ago
13

Verifying Properties of logarithms In Exercise,use a graphing utility to verify that the functions are equivalent for x > 0.

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

Answer:

Applying Quotient and power rule. Graphically, for x>0 both curves coincide.

Step-by-step explanation:

1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:

lnx=log_{e}x\\\\f(x) = ln({\frac{x^{2}}{4}})\Rightarrow f(x)=ln{x^2}-ln4\Rightarrow f(x)=2lnx-ln4\\g(x) = 2 ln x - ln 4

2) Check the graph below to see this equivalence. to see x>0 they  both coincide.

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LekaFEV [45]
4 \dfrac{3}{5} \times \dfrac{5}{12} =

= \dfrac{23}{5} \times \dfrac{5}{12}

You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.

= \dfrac{23 \times 5}{5 \times 12}

Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.

= \dfrac{23 \times 5}{12 \times 5}

= \dfrac{23}{12}

= 1 \dfrac{11}{12}
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What is this answer?
Shtirlitz [24]

Answer:

1/2

Step-by-step explanation:

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