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mixas84 [53]
2 years ago
7

7. Which of these is equivalent to the expression 8+8+8+8+12?

Mathematics
1 answer:
LenKa [72]2 years ago
4 0

Answer:

Step-by-step explanation:

There are four 8s, so s should represent one 8.

The 12 is made up of 4 * 3, so B should be the answer.

Answer: B or 4(s + 3)

When the brackets are removed, you get 4s + 12

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Shirts are onsale at 3 for $15.50. how many shirts can you buy with $139.50.
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If one shirt is sold for $15.50, the amount of shirts you'd be able to buy with $139.50 is 9.

Multiply 9 by 3 and you get your answer: 27 Shirts
5 0
4 years ago
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Type the correct answer in the box. Write the standard form of the quadratic equation modeled by the points shown in the table b
White raven [17]
Y =ax² + bx +c

1) Point (0,7)

7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7

2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b

4)  a+b= - 3, ----> b= -3 - a (substitute in the second equation)
    2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2

5) a+b= - 3
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b = -5

y=2x² - 5x + 7

8 0
3 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
A class of 24 students was asked to identify a team sports in which they have participated their responses are shown in the line
nekit [7.7K]
There are 28 responses recorded.
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mart [117]

6x=4+3/8x

That will be the answer

4 0
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