since they're similair then similair sides will be proportional
CB is similair to EF
\frac{6}{8}86 = \frac{3}{4}43
same thing if you try with the hypotenuse AB similair to DE
\frac{13.5}{18}1813.5 = \frac{3}{4}43
So, if you multiply r (DF) by 3/4 you will get the similair side AC
rx 3/4=12
r= 12÷ 3/4
<h3>r=16.</h3>
<h2>i HOPE IT'S HELP </h2><h3 />
Answer:
0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability that a sophomore non-Chemistry major
Out of 92 students, 9 are non-chemistry major sophomores. So

Then a junior non-Chemistry major are chosen at random.
Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
Answer:
D is the answer
Step-by-step explanation:
don't froget my cake!! :)
15. If a+b=6 and ab=9 that means a and b must each equal 3. Then plug it into the equation and solve. (3)3+(3)2 = 15
Answer:
it should be 67/65 or if in mixed number form : 1 2/65