The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
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Answer:
Y = 2
X = 3
Step-by-step explanation:
Substitution:
6(4y-5) - y = 16
24y-30-y=16
23y=46
Y = 2
So then:
6x-2 = 16
6x = 18
X = 3
Answer is : 1.2 geometric series
Answer:
AC=7.5 cm
CB=10.5cm
Step-by-step explanation:
Since we don't know the distance from C to B, we can label it as x. Our equation will be x+(x-3)=18. Simplify that so it is 2x-3=18. Add 3 to both sides and get 2x=21. x=10.5 So AC=7.5 cm and CB is 10.5 cm
Answer:
1/2
Step-by-step explanation:
As a decimal it is 0.5 which is exactly between 0 and 1
Hope this helps you :) !
