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Soloha48 [4]
3 years ago
14

Using the graph below, if f(x) = 4, find x.

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0
3 I think is the answer
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the spoke of a wheel reaches from the center of the wheel to its rim if the circumstance of the rim of the wheel is 27 inches ho
aleksley [76]
Circumference = 2*pi*r = 27"
Solve for r
r=27"/(2*pi)
=27"/(2*3.14159265)
=4.297..."
=4.30" (to the nearest hundredth of an inch)

7 0
3 years ago
Which is M=9pm solved for p
zaharov [31]
<h2>Answer:</h2>

<u>The value of </u><u>p :M/9m</u>

<h2>Explanation:</h2>

As we have been given value of M

Value of M=9pm

So we can find value of p from here by simple mathematics rule

M=9pm

divide both side with 9m so

M/9m=9pm/9m

we get value of p so M/9m=p.

we can write it as p=M/9m

6 0
4 years ago
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

(7x + 7x) + ( \frac{1}{2}  -  \frac{15}{2} )

5) simplify.

14x - 7

6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

7 0
3 years ago
Estimates show that there are 1.4*10^8 pet fish and 9.4*10^6 pet reptiles in the United States.
Readme [11.4K]
\bf \stackrel{fish}{1.4\times 10^8}~~+~~\stackrel{reptiles}{9.4\times 10^6}&#10;\\\\\\&#10;\stackrel{fish}{140000000}~~+~~\stackrel{reptiles}{9400000}\implies &#10;\begin{array}{rrrrllll}&#10;140000000\\&#10;+9400000\\&#10;\text{\textemdash\textemdash\textemdash\textemdash\textemdash}\\&#10;149400000&#10;\end{array}\implies 1.494\times 10^8
5 0
3 years ago
Find the total area of a cylinder whose radius is 2 cm and height is 4 cm.
kolezko [41]

Answer:

78.95cm^2

Step-by-step explanation:

The equation for a cylinder is rπ^2 · h

2π²·4≈78.95

4 0
3 years ago
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