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inessss [21]
2 years ago
7

What is the quotient in simplest form? 12 7 7 O 36 3 O 5 5

Mathematics
1 answer:
Firdavs [7]2 years ago
6 0
The answer is 4/7. Hope this helps
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Solve 3x2 + 4x = 2<br>I need it solved with the quadratic formula​
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3x2+4x=2
6+4x=2
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3 years ago
Which is equivalent to 80 1/4x
vichka [17]

Answer:

20x

Step-by-step explanation:

\frac{80}{4}=\frac{20}{1}=20

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3 years ago
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62 is divisible by which of the following numbers
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D.

Step-by-step explanation:

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Grade 8 Math
aksik [14]
Read this sentence in the problem carefully.
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7 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
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