Answer:
BC = q +p
Step-by-step explanation:
<h3>b)</h3>
Here's one way to get there. Two vector sums are the same if they have the same starting and ending points. The sum AC can be expressed two ways:
AB +BC = AD +DC
p +BC = q +2p . . . . . . using givens, and your result from part (a)
Subtract p from both sides:
BC = q +p
Answer:
Option B is right
Step-by-step explanation:
We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent.
These three concur at a point called the circumcentre of the triangle.
When we draw perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistance from A and B.
When we take the point of intersection of perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short this is equidistant from all 3 vertices and hence is centre of circumcicle of triangle ABC
Answer:
-41
Step-by-step explanation:
g(x) = 3x + 1
g(-14) = 3*(-14) + 1
= -42 + 1
= -41
Answer: 78
Step-by-step explanation: You do 3 * 26 to get your answer.
Use p.e.m.d.a.s.
<span>first multiply 6Q and 8Q = 48Q
then subtract 58Q and 48Q = 10Q
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