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deff fn [24]
3 years ago
6

Which of the following samples would meet the "random" condition?

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

Brother there's nothing there

Step-by-step explanation:

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Two functions are given.
ArbitrLikvidat [17]

Hi

f(x) = g(x)   if    -x²+3x-2   - ( -x+1) = 0

                      -x² +3x-2 +x-1 = 0

                      -x² +4x -3 = 0

To solve, tou have to use the general method of resolution of a quadratic fonction.  

To determine if it's has a solution in R, let's calculate  Δ

Δ = (4)² - 4 * (1) *(-3)

Δ = 16 +12

Δ= 28  

as Δ≥ 0  so  the function allow two solution within R  

so S 1 =  ( -4 +√28) / 2            S 2 =   (-4 -√28 ) /2

    S1 =   ( -4 + 2√7) /2            S2 =    (-4 - 2√7) /2

    S1 =    (2 (-2 +√7) /2            S2      2 (-2 -√7)   /2

    S1 =    -2 +√7                       S2 =      -2 -√7

So the two function  are equal   twice. one  for   x = -2 +√7  and second x = -2-√7

4 0
3 years ago
Given the function f(x) = x3 + 2x2 − 3x − 5, what is the resulting function when f(x) is shifted to the right 1 unit? f(x + 1) =
xz_007 [3.2K]
When a function is shifted to the right by 1 unit it is moved towards the negative side so we would be adding -1 to the value of x. The function f(x) would be f(x-1). To determine the resulting function, we substitute to the parent function (x-1) to x. We do as follows:

<span>f (x) = x^3 + 2x^2 − 3x − 5
</span>f (x-1) = (x-1)^3 + 2(x-1)^2 − 3(x-1) − 5
f (x-1) = x^3 - 3x^2 + 3x - 1 + 2(x^2 - 2x + 1) - 3x + 3 - 5
f (x-1) = x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5
f (x-1) = <span>x^3 - x^2 - 4x - 1 

Therefore, the correct answer is the last option.</span>
5 0
3 years ago
Help me please. I really need it​
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

can you post a better pic please

6 0
3 years ago
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2. Given AMAR, solve for the m&amp;M. Round to the
Naddik [55]

Answer:

what is the question

Step-by-step explanation:

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