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OleMash [197]
2 years ago
5

What is the slope? Please help

Mathematics
2 answers:
ss7ja [257]2 years ago
8 0

Answer:

-1/2

Step-by-step explanation:

slope = rise/run = (difference in y)/(difference in x)

Look for two points that are easy to read since they fall on grid lines intersections.

For example, pick point (0, 3) as the first point.

Pick point (2, 2) as the second point.

We start at the first point (0, 3) and need to go to point 2 by using only vertical and horizontal moves.

Start at (2, 2). Go down 1 unit. That is a rise or a change in y of -1.

Now go right 2 units. That is a run or a change in x of 2.

slope = rise/run

slope = -1/2

Answer: -1/2

tresset_1 [31]2 years ago
7 0

Answer:

Slope is -1/2

step by step explanation

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vekshin1

Answer:

k=6

Step-by-step explanation:

Line partition formula

1/b(x2-x1)+x1, 1/b(y2-y1)+y1

Where b is the number partitions.

We know the x values so Subsitue 17 for x2 and 2 for x1. and we know this value must equal 7.

1/b(17-2)+2=7

1/b(15)=5

1/b=1/3

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so the partition is 1/3

\frac{1}{3} (17 - 2) + 2 = 7

So let find the y coordinate

\frac{1}{3} (8 - 5) + 5 = 6

So our y coordinate is 6.

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3 years ago
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
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Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Distance is generally a positive number. (Displacement, or position may be negative, as in this case.) If the sub started at 0 feet and went lower than -24 feet, it traveled a distance of more than 24 feet (greater than 24 ft).

Of the numbers listed, the only one lower than -24 is -27.

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