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3 years ago

Please help 30 points will give brainliest

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Answer:

thats correct

Step-by-step explanation:

Gemiola [76]3 years ago

3 0

Answer:

60°

Step-by-step explanation:

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Dan makes a pineapple sorbet. He uses 3 lemons. Work out how many people he makes pineapple sorbet for.

seropon [69]

Answer:

N/A

Step-by-step explanation:

There is not enough information to answer with a number.

6 0

3 years ago

X to the power of 3 - 7x + 6 factorise please whole step by step

Over [174]

Answer:

$(x + 3)(x - 2)(x - 1)$

Step-by-step explanation:

${x}^{3} - 7x + 6$

Factor using Rational Root Theorem.

This means our possible roots are

positve or negative (1,2,3,6). If we try positve 1, it is indeed a root.

This means that

$(x - 1)$

is a root.

We can divide the top equation by the root (x-1). Our new equation is

$( {x}^{2} + x - 6)$

Now we can factor this completely

$(x + 3)(x - 2)$

So this equation in factored form is

$(x + 3)(x - 2)(x - 1)$

8 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$