Prove using identities A minus A intersection B = A-B
1 answer:
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We just need to see everything that is not x as a number.
if I asked
we would solve it by combining like terms first. but, if I tell you not to do that, we would add 9 and 7(2) to both side and end up with
we would then divide both sides by 7
math is always math... it's just how we look at it. so, do the same steps!
add 9 and 7z to both side
divide both sides by 7
if I asked
we would solve it by combining like terms first. but, if I tell you not to do that, we would add 9 and 7(2) to both side and end up with
we would then divide both sides by 7
math is always math... it's just how we look at it. so, do the same steps!
add 9 and 7z to both side
divide both sides by 7
Answer: A
Step-by-step explanation:
The line 'd' separates the square into two triangles. Since the side lengths are equal, the angle is 45°. We need the line separating the two 90° angles, that I am going to define as 'z'. We can use the sine function.
z = 5
To solve for x, we can use sine again but for the 30 degree angle.