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Alexus [3.1K]
4 years ago
15

What is the volume of the cylinder with a diameter of 6 centimeters and a height of 8.6 centimeters? Round your answer to the ne

arest tenth
Select the best answer from the choices provided.

A. 243.0 cm
B. 1620 cm
972.1 cm
D. 309.6 cm​
Mathematics
1 answer:
blsea [12.9K]4 years ago
8 0

Answer:

1620 :B

Step-by-step explanation:

22/7×3×3×8.6=162.17

162.7 rounded off to the nearest tenth is

the 1620

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What is the equation for the total cost
drek231 [11]
The correct answer is A
5 0
3 years ago
a farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar
xenn [34]

The constraint for the maximum enclosed area is the amount the farmer is

willing to spend on fencing.

The width of the plot that will give the most area, y = <u>83.</u>\underline{\overline 3}<u> feet</u>

The length of the plot that will give the most area, y = <u>125 feet</u>

Reasons:

The given parameters are;

The cost of fencing per foot = $20

The maximum amount the farmer is willing to spend = $5000

Number of sides of fencing = 3 sides

Cost of the west side of the = Split with neighbor

Solution:

Let, y, represent the length of the fence, and let <em>x</em> represent the width of

the fence, we have;

Length of fence required = y + 2·x

Cost of the fence = 20·y + 20·x + (20÷2)·x = 20·y + 30·x

Therefore;

Maximum amount to be spent on the fence, 5000 = 20·y + 30·x

\therefore y = \dfrac{5000 - 30 \cdot x}{20}  = 250 - \dfrac{3}{2} \cdot x

y =  \mathbf{250 - \dfrac{3}{2} \cdot x}

Area of a rectangle = Length × Width

The enclosed rectangular area of the fencing, A = y × x

\therefore A = \left(250 - \dfrac{3}{2} \cdot x\right) \cdot x = 250 \cdot x - \dfrac{3}{2} \cdot x^2

\therefore A  =  -\mathbf{ \dfrac{3}{2} \cdot x^2 + 250 \cdot x}

The leading coefficient of the quadratic function of the area is negative,

therefore, the function only has a maximum point.

At the point of the most area, the slope, \dfrac{dA}{dx} = 0

Finding the value of <em>x</em> at the maximum point, we get;

\dfrac{dA}{dx} = \mathbf{ \dfrac{d}{dx} \left( 250 \cdot x - \dfrac{3}{2} \cdot x^2\right)} = 250- 3 \cdot x = 0

Therefore;

\mathrm{ The \ width \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ x = \dfrac{250}{3} \ feet = \underline{83.\overline 3 \ feet}

\mathrm{ The \ length \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ y =  250 - \dfrac{3}{2} \times  \dfrac{250}{3} = 125

The length of the plot that will give the most area, y = <u>125 feet</u>

Learn more here:

brainly.com/question/16337916

brainly.com/question/16545343

6 0
3 years ago
Prove that cos1° cos2° cos3°...cos180° = 0​
leva [86]

Answer:

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4 0
2 years ago
Simplify 5^2 times 5^4
Elanso [62]

Answer:

5^2 = 25 5^4 = 50

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1. A catering company’s recipe for salad uses a ratio of 2 c of dressing to 4 lb of vegetables. (a) Draw a model for the ratio.
IRISSAK [1]
1. ratio = 2 c of dressing / 4 lb of vegetables

Use two variables: d for the number of c of dressing and v for the number of pounds of vegetables.

Then d / v = 2/4 = 1/2 => d = v/2

Now you can make a table

v     d  

2    1

4    2

6    3

8    2

And you can draw a line for the points (2,1); (4,2); (6,3), (8,4) ... the slope of the graph is the ratio = 1/2

b) I already did it above as part ot the explanation: d/v = 1/2
3 0
4 years ago
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