Answer:

Step-by-step explanation:
The distance between the focus and the directrix is the vertical distance from the point to the line:
1 -(-3) = 4
The vertex is half that distance between the point and the line, so is at x=2 and ...
y = (-3 +1)/2 = -1
The vertical scale factor of the quadratic is 1/(4p) where p is the distance from vertex to focus. Here, that distance is 2, so the equation in vertex form is ...
y = (1/(4·2))(x -2)² -1
y = (1/8)(x -2)² -1
_____
<em>Check</em>
Any point on the parabola is equidistant from the focus and directrix. This is easily checked at the vertex, which is halfway between focus and directrix, and at the points having the same y-value as the focus. Those two points are (-2, 1) and (6, 1), both of which are 4 units from the focus and 4 units from the directrix.
Answer:
u just add it
Step-by-step explanation:
Line a and b are perpendicular
The Answer is: 5 (5c+3)
Step-by-step explanation:
Should have the ordered pairs of
(-4,4) (-3,3) (-2,2) (-1,1) (0,0) (1,1) (2,2) (3,3).
Will look like a V when graphed. Reason being is if you take the absolute value of anything you are basically just dropping the negative sign as it is how far away it is from 0.