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3 years ago

CORRECT ANSWER WILL GET BRAINEST (50 points)

Mathematics

2 answers:

rosijanka [135]3 years ago

5 0

Rick had 1,202 hits and Pedro had 1,477.

Let's put this into steps:

⇒ 2679-275=

⇒2404

⇒2402/2=

⇒1202

We have Ricky's number of hits. Now we keep going for Pedro's.

⇒1202 +275=

⇒1477

You can tell if it's their numbers by adding them together and getting 2679 back.

Hence, Ricky had 1,202 hits and Pedro had 1,477.

Katarina [22]3 years ago

3 0

Answer:

Pedro had 1,479 base hits and Ricky had 1,200 base hits :)

Step-by-step explanation:

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

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3 years ago

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NEED HELP ASAP. a sphere has a surface area of 36pi ft2. find the volume of the sphere.

max2010maxim [7]

Answer:

Approximately: 200.76π or 630.39

Step-by-step explanation:

Surface area for sphere formula: A = 4π(r^2)

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(36/4)π = [4(r^2)]/4

9π = r^2

28.26 = r^2 (since π equals 3.14)

√28.26 = √r^2

r ≈ 5.32

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V = 4/3(π)(5.32^3)

V ≈ 4/3(π)(150.57)

V ≈ 200.76π

V ≈ 630.39

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Step-by-step explanation:

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