Ask question

Ask question

All categories

3 years ago

12

A high school track team's long jump record is 24 ft 9 1/4 in. This year, Arthur's best long jump is 24 ft 3 1/2 If long jump

s are measured to the nearest quarter inch, how much farther must jump to break the record?

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer: 5 3/4 inches

Step-by-step explanation:

u subtract then complete.

lana [24]3 years ago

4 0

Answer:

5 3/4 inches

Step-by-step explanation:

Given that :

Long jump record held = 24 ft 9 1/4 in

Arthur's best long jump record = 24 ft 3 1/2 in

How much further must ARTHUR jump to brake the record :

Long jump record - Arthur's best jump

[24 ft 9 1/4 in] - [24 ft 3 1/2 in]

24 ft - 24 ft = 0

9 1/4 in - 3 1/2 in

37 / 4 in - 7 /2 in

L. C. M of 4 and 2 = 4

(37 - 14) / 4 inches

23 /4 inches

= 5 3/4 inch

You might be interested in

Please help show work I beg <br><br> A 5<br> B 17 <br> C 34 <br> D 3

Gemiola [76]

Answer: 5

Because the two angles are congruent, these sides are congruent, so:

5x-8=2x+7
3x=15
x=5

7 0

3 years ago

Divide 180 degrees by the ratio 4:5:9, Help Please

mixas84 [53]

Add all the numbers in the ratio together to get 18 then divide 180 by 18 to equal 10. then times that by each individual number in the ratio. so the answer is 40:50:90

7 0

3 years ago

Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. How interest will he have earned a

agasfer [191]

We have been given that Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. We are asked to find amount of interest earned at the end on 8 years.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$3.25\%=\frac{3.25}{100}=0.0325$

$A=6500(1+\frac{0.0325}{1})^{1\cdot 8}$

$A=6500(1+0.0325)^{8}$

$A=6500(1.0325)^{8}$

$A=6500(1.2915775352963673)$

$A=8395.253979$

Now we will subtract principal amount from final amount to find amount of interest as:

$\text{interest}=8395.253979-6500$

$\text{interest}=1895.253979\approx 1895.25$

Therefore, Nicolas would have earned $1895.25 in interest at the end of 8 years.

7 0

3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

<u>Answer-</u>

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

3 years ago

What is the relationship between the value of the digit 3 in 4,231 and in the value of the digit 3 in the number 3,421?

Marina CMI [18]

Answer:

A.

In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.

Step-by-step explanation:

We can see that the value of 3 In 4231 is in ten while the value of 3 in 3421 is in thousands.

So to get the actual division factor, let's take 3300 and divide it by 30,

3300/30 = 110

So it's clear already, that the value of 3 in 4231 is 110 times less to the value in 3421

4 0

3 years ago