Answer:
C'A' = 10units (A)
Question
A complete question related to this found at brainly(question ID 2475535) is stated below.
Triangle ABC was dilated using the rule Dy, 5/4
If CA = 8, what is C'A'?
10 units
12 units
16 units
20 units
Step-by-step explanation:
Given:
Scale factor = 5/4
CA = 8units
Find attached the diagram for the question.
This is a question on dilation. In dilation, figures have the same shapes but different sizes.
Y is the center of dilation
Lengths of ∆ABC: CB, AB, CA
Lengths of ∆A'B'C': C'B', A'B', C'A'
C'B' = scale factor × CB
A'B' = scale factor × AB
C'A' = scale factor × CA
C'A' = 5/4 × 8
C'A' = 40/4
C'A' = 10units (A)
Practice, practice, practice. And ask questions.
The expected value if I have to pick one package given the price I would have to pay is $0.11.
<h3>What is the expected value?</h3>
The expected value is the cost you would have to pay subtracted from the total value of one package.
Total value of one package =[ (15 x 0.60) + (5 x 0.3) + (20 x 0.7)]/ (20 + 15 + 5) = $0.61
Expected value = $0.61 - $0.50 = $0.11
To learn more about expected value, please check: brainly.com/question/27624788
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Answer:the ANS to 4 significant figures is 51.92
Step-by-step explanation:u first find the area of the whole chord which is 150 divided by 360 multiplied by the π × 7^2 subtracted from the area of The triangle by doing 1/2×7×7sin150. I hope it helps
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.