All categories

3 years ago

The radius of a circle is 10 inches. What is the area of a sector bounded by a

Mathematics

1 answer:

guajiro [1.7K]3 years ago

8 0

The answer is 180/100

You might be interested in

Two less than 2 times a numberis the same as the number plus 64.What is the number?

bixtya [17]

The number is 66 hope this helped

3 0

3 years ago

Read 2 more answers

How do i figure out 23 and 24 please help!!

mixas84 [53]

Do the (3x=6) first than the outside of the prenthesies

5 0

3 years ago

Read 2 more answers

A drug that it will decrease the bacteria cells by 5% every hour. If you start with 1500 bacteria cells, how many will be presen

scZoUnD [109]

after 8 hours there are 995 bacteria cells left

let y be the amount after 8 hours

the multiplying factor is 100 - 5 = 95 % = 0.95

y = 1500 × $(0.95)^{8}$ = 995

5 0

3 years ago

What is the coefficient of the x-term in the expression 4x+5xy-2y

solmaris [256]

Answer:

Step-by-step explanation:

6 0

3 years ago

Find an equation of the tangent line to the hyperbola x2 a2 − y2 b2 = 1 at the point (x0, y0).

nalin [4]

The equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

To find the tangent to the hyperbola $\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }$ at (x₀, y₀), we differentiate the equation implicitly to find the equation of the tangent at (x₀, y₀).

So, $\frac{d}{dx} (\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }) = \frac{d0}{dx}\\\frac{d}{dx} \frac{x^{2} }{a^{2} } - \frac{d}{dx}\frac{y^{2} }{b^{2} }= 0\\\frac{2x }{a^{2} } - \frac{dy}{dx}\frac{2y }{b^{2} } = 0\\\frac{2x }{a^{2} } = \frac{dy}{dx}\frac{2y }{b^{2} } \\\frac{dy}{dx} = \frac{b^{2}x }{a^{2}y }$

So, at (x₀, y₀)

$\frac{dy}{dx} = \frac{b^{2} x_{0} }{a^{2} y_{0} }$

So, the equation of the tangent line is gotten from the standard equation of a line in point-slope form

So, $\frac{y - y_{0} }{x - x_{0} } = \frac{b^{2} x_{0} }{a^{2} y_{0} } \\y - y_{0} = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) \\y = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) + y_{0} \\y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

So, the equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

Learn more about equation of tangent line here:

brainly.com/question/12561220

3 0

3 years ago