Y=8/2
y=4!!!!!!!!!!!!!!!!!
Here’s the graph. I hope this is right
Answer:
$68
Step-by-step explanation:
We have been given the demand equation for Turbos as
, where q is the number of buggies the company can sell in a month if the price is $p per buggy.
Let us find revenue function by multiplying price of p units by demand function as:
Revenue function: ![pq=p(-4p+544)](https://tex.z-dn.net/?f=pq%3Dp%28-4p%2B544%29)
![pq=-4p^2+544p](https://tex.z-dn.net/?f=pq%3D-4p%5E2%2B544p)
Since revenue function is a downward opening parabola, so its maximum point will be vertex.
Let us find x-coordinate of vertex using formula
.
![\frac{-b}{2a}=\frac{-544}{2\times -4}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%7D%7B2a%7D%3D%5Cfrac%7B-544%7D%7B2%5Ctimes%20-4%7D)
![\frac{-b}{2a}=\frac{-544}{-8}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%7D%7B2a%7D%3D%5Cfrac%7B-544%7D%7B-8%7D)
![\frac{-b}{2a}=68](https://tex.z-dn.net/?f=%5Cfrac%7B-b%7D%7B2a%7D%3D68)
The maximum revenue would be the y-coordinate of vertex.
Let us substitute
in revenue formula.
![pq=-4(68)^2+544(68)](https://tex.z-dn.net/?f=pq%3D-4%2868%29%5E2%2B544%2868%29)
![pq=-4*4624+544(68)](https://tex.z-dn.net/?f=pq%3D-4%2A4624%2B544%2868%29)
![pq=-18496+36992](https://tex.z-dn.net/?f=pq%3D-18496%2B36992)
![pq=18496](https://tex.z-dn.net/?f=pq%3D18496)
Therefore, the company should sell each buggy for $68 to get the maximum revenue of $18,496.
The answer to this is 30.41 due to the zero the answer cannot be moved on so it will stay the same.