Is the following relation a function?

Mathematics

2 answers:

mel-nik [20]2 years ago

6 0

Answer:

Step-by-step explanation:

the x value (-1) repeats therefore it ain't a function

choli [55]2 years ago

3 0

No it is not a function

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At 8:00 a.m., there were t inches of snow on the ground. At 5:00 p.m., there were 3t inches of snow on the ground. How many more

Anastaziya [24]

we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

3t- t = 2t

And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

t = (12in)/3 = 4 in

Replacing that in the difference of heights:

2t = 2*4in = 8in

From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

If you want to learn more about linear equations:

brainly.com/question/1884491

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3 0

2 years ago

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W

Travka [436]

Complete question:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

$A"B" = \frac{AB}{2}$

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

$A"B" = AB * \frac{1}{2}$