To simplify, we need to find a number that can divide both the numerator and denominator equally. Can you find a number that will do this? I can't. So it is already simplified.
Answer:
x = -6/5
Step-by-step explanation:
distribute -4 on the left side of the equation first, then distribute 2 on the right side of the equation to get:
16x - 4 - 4x = 2x - 14 - 2
combine 'like terms':
12x - 4 = 2x - 16
subtract '2x' from each side to get:
10x - 4 = -16
add 4 to each side to get:
10x = -12
x = -12/10 or x = -6/5
Factor:
3x^2 + 27
= 3(x^2 + 9)
Answer is 3(x^2 + 9), when factored.
A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2
B) (3x - 9i)(x + 3i)
= (3x + - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2
C) (3x - 6i)(x + 21i)
= (3x + - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
= - 126i^2 + 57ix + 3x^2
D) (3x - 9i)(x - 3i)
= (3x + - 9)(x + - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x
Hope that helps!!!
-5a^2 - 7a = -a x (5a + 7)
let me know if you have any other questions
:)
Answer:
-1/53
Step-by-step explanation:
