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zimovet [89]
3 years ago
7

a model helicopter burns 1 2/5 ounces of fuel per minute. at that rate, how much fuel is needed for a 7 1/2 minute flight

Mathematics
1 answer:
bixtya [17]3 years ago
4 0
The model helicopter would burn 10.5 ounces of fuel in 7 1/2 minutes. You would first multiply 1.4 (1 2/5 ounces of fuel) by 7 minutes to get 9.8 ounces of fuel. Then, divide 1.4 by 2 to account for the thirty seconds of the flight ( thirty seconds is half of a minute, or 1/2) to get 0.7, add 0.7 by 9.8, and get 10.5 ounces of fuel in the process.
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5. Use the Pythagorean theorem to estimate the length of the unknown side of the right triangle. Explain why
photoshop1234 [79]

Answer:

Step-by-step explanation:

a^2 + b^2 = c^2

6 = b

c= 8

a=?

now u just replace

a^2 + 6^2 = 8^2

a^2 + 32 = 64

a ^2 = 64-32

a^2 = 32

\sqrt a^{2}  = \sqrt32

a     = 5.65685424949

if you rounded

a = 5,7

3 0
2 years ago
After selecting 180 of its employees to from a new division, a company discovers that engineers outnumber analysts by a 3:1 rati
nikdorinn [45]

Answer:

I think its 90

Step-by-step explanation:

3x plus 1x is 4x divide 180 but 4 and get 45 so that meab there are 135 and 45

you need 90 more analysts to have a 1 to 1 ratio

3 0
3 years ago
Need help with question 2
Alex777 [14]
The answer is y= -x-1
8 0
3 years ago
To qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 an
kolbaska11 [484]

Answer:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

Step-by-step explanation:

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X ~ N (200,20)

For u = 200 and o = 20

For this case we can use the z score in order to solve this problem, given by this formula:

Z = x-u/o

For this part we want to find a value a, such that we satisfy this condition:

P (X > a) = 0.1 (a)

P (X < a) = 0.9 (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P ( X < a) = P (X-u/o < a - u/o) = 0.9

P (z < a-u/o) = 0.9

But we know which value of z satisfy the previous equation so then we can do this:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

3 0
2 years ago
The area of a trapezium is 384cm². Its parallel sides are in the ratio3 : 5 and the perpendicular distance between them is 12 cm
Pani-rosa [81]
Area of trapezium=384 square cm
Ratio of parallel sides=
Distance between parallel sides=h=12 cm
5 0
3 years ago
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