a model helicopter burns 1 2/5 ounces of fuel per minute. at that rate, how much fuel is needed for a 7 1/2 minute flight

1 answer:

4 0

The model helicopter would burn 10.5 ounces of fuel in 7 1/2 minutes. You would first multiply 1.4 (1 2/5 ounces of fuel) by 7 minutes to get 9.8 ounces of fuel. Then, divide 1.4 by 2 to account for the thirty seconds of the flight ( thirty seconds is half of a minute, or 1/2) to get 0.7, add 0.7 by 9.8, and get 10.5 ounces of fuel in the process.

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Factor and add steps please<br><br> 81u^6+192

attashe74 [19]

ANSWER : (9u - 8)2

STEPS:

Step-1 : Multiply the coefficient of the first term by the constant 81 • 64 = 5184

Step-2 : Find two factors of 5184 whose sum equals the coefficient of the middle term, which is -144 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -72 and -72
81u2 - 72u - 72u - 64

Step-4 : Add up the first 2 terms, pulling out like factors :
9u • (9u-8)

Step-5 : Add up the four terms of step 4 :
(9u-8) • (9u-8)
Which is the desired factorization

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1 year ago

What’s is the answer

Rzqust [24]

Answer:

383.5

Step-by-step explanation:

3835 ÷ 10 = 383.5

Move the 5 to the Tenths

4 0

2 years ago

Read 2 more answers