All categories

2 years ago

What is 62 1/2% of 10?

Mathematics

1 answer:

mina [271]2 years ago

4 0

Answer:

6.25%

Step-by-step explanation:

10 x .625 = 6.25 this is the answer

You might be interested in

If C is the incenter of ∆AMD, m∠A M C = 3 x + 6 and m∠ DMC= 8 x − 49.

Sunny_sXe [5.5K]

<h2>Answer:</h2><h2>51.</h2>

Hope this will help you lot.

8 0

2 years ago

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviati

antiseptic1488 [7]

Your answer should be 6.4 if you attempt to solve this. I hope this helps your question!

4 0

3 years ago

Read 2 more answers

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Elaine has a piece of wire that is 2.16 meters long.Dikembe has a piece of wire that is 2.061 meters long. whose piece of wire i

vesna_86 [32]

Elaine's piece is bigger because when you look at the tenths place, you can see that 1 is bigger than 0.

4 0

3 years ago

Read 2 more answers

Ted likes to run long distances. He can run 20 kilometers in 95 minutes. How far will Ted run in 285 minutes? (numeric only) *

nikklg [1K]

Answer:

He will run 60 kilometers.

Step-by-step explanation:

285 / 95 = 3

20 x 3 = 60

3 0

2 years ago