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3 years ago

Neena is listening to a song. It has a consistent beat. She counts 11 beats in

Mathematics

1 answer:

galben [10]3 years ago

7 0

Answer:

11beats / 1 second = 660 beats /1 minute

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What is an equation of a line which passes through (6,9) and is perpendicular to the line whose equation is 4x − 6y = 15?

Svetllana [295]

Given:

The equation of the line passes through the point (6,9) and is perpendicular to the line whose equation is $4 x-6 y=15$

We need to determine the equation of the line.

Slope:

Let us convert the equation to slope - intercept form.

$-6 y=15-4x$

$y=\frac{2}{3}x-\frac{5}{2}$

From the above equation, the slope is $m_1=\frac{2}{3}$

Since, the lines are perpendicular, the slope of the line can be determined using the formula,

$m_1 \cdot m_2=-1$

$\frac{2}{3} \cdot m_2=-1$

$m_2=-\frac{3}{2}$

Therefore, the slope of the equation is $m=-\frac{3}{2}$

Equation of the line:

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (6,9) and the slope $m=-\frac{3}{2}$ in the above formula, we get;

$y-9=-\frac{3}{2}(x-6)$

Simplifying the terms, we get;

$2(y-9)=-3(x-6)$

$2y-18=-3x+18$

$3x+2y=36$

Thus, the equation of the line is $3x+2y=36$

3 0

3 years ago

I really need help with this and how you got it please 10 points!!

Kamila [148]

Answer:

1 and 7 are congruent

2 and 5 are supplementary

4 and 6 are congruent

3 and 8 are supplementary

8 0

3 years ago

The ratio of boys to girl in a certain class is 4:7. if there are 33 students in the class, how many of them are girls.

Elden [556K]

Your answer is that 21 are girls

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3 years ago

how many times can a rectangle be reflected across an axis of symmetry so that its carries onto itself

Ostrovityanka [42]

2 times, you can fold it without no overlapping on any line

3 0

3 years ago

Read 2 more answers

The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the

Mrrafil [7]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7$

8 0

3 years ago