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cricket20 [7]
2 years ago
11

Factored form of 2x^2+x-3 must show work

Mathematics
1 answer:
frozen [14]2 years ago
4 0

Answer:

(2x+3)(x - 1)

Step-by-step explanation:

Since there is no common number to factor by we must approach this problem differently:

Step 1:

Multiply leading coefficient (2) by the constant term (-3)

2 x -3 = -6

Step two:

Find two numbers that multiply to -6 but add to the middle coefficient (1).

You should find these numbers to be 3 and -2

Step 3:

Replace 1x in the equation with your found numbers

2x^2 - 2x + 3x - 3

Step 4:

Take out the greatest common factor from the first two numbers, and the last two numbers.

For 2x^2 - 2x the greatest common factor would be 2x

For 3x - 3 the greatest common factor would be 3.

Step 5:

Factor out the found common factors

2x(x-1) + 3(x-1)

The values inside the bracket should be the same.

Step 6:

Factor out (x-1)

(x - 1)(2x + 3)

Therefore the factored form is (2x + 3)(x - 1)

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№17
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№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
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Answer: x₁ = 1 + √3.5
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