Answer:
In the given figure, line segment is constructed on the triangle parallel to line segment . ... This line can then be considered as a transversal of these parallel lines. Angle and angle are therefore corresponding angles. And as they're corresponding, this means that they're equal.
Answer:
194.8 miles
Step-by-step explanation:
510 - 315.2 = 194.8
Hope this helps!
Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC = 
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² = 
+ x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
Answer:
15 hours
Step-by-step explanation:
is the number of hours that Liam volunteered in the first month
The next month he volunteered 
times the time he volunteered the first month.
Total time he volunteered in the two months is 40 hours so
Time he volunteered in the first month is 15 hours.
