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Mice21 [21]
3 years ago
11

2. Given the graph below, answer the following questions.

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

y=2x+3

y=2x+3

y=2x+3

y=2x+3

kow [346]3 years ago
6 0
Function A is increasing
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Percent notation what is the meaning
mario62 [17]

Answer:

In mathematics, a percentage (from Latin per centum "by a hundred") is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", or the abbreviations "pct.", "pct"; sometimes the abbreviation "pc" is also used. A percentage is a dimensionless number (pure number).

Step-by-step explanation:

7 0
4 years ago
What is the answer to 4(5x+8+3p)
il63 [147K]
To simplify this use the distributive property.

4(5x)= 20x
4(8)=32
4(3p)=12p

Your simplified answer is 
20x+12p+32
5 0
3 years ago
Read 2 more answers
Sorry I'm not good at math but I just want to learn how to do this
kolezko [41]
The answer is 8.6. I hope this helped you out!
4 0
4 years ago
3. Louis can run 5/8 mile in ¼ hour. What is his rate in miles per hour?
irga5000 [103]
He can run 2.5 miles per hour
3 0
4 years ago
Find the absolute maximum and minimum values of f on the set D. f(x, y) = x3 − 3x − y3 + 12y + 1, D is quadrilateral whose verti
mojhsa [17]

D is the set of points,

\left\{(x,y)\mid-2\le x\le2,x\le y\le3\right\}

Check for critical points:

f(x,y)=x^3-3x-y^3+12y+1\implies\begin{cases}f_x=3x^2-3=0\implies x=\pm1\\f_y=-3y^2+12=0\implies y=\pm2\end{cases}

Of these 4 points, only 2 belong to D, (-1, 2) and (1, 2), for which we have

\begin{cases}f(-1,2)=19\\f(1,2)=15\end{cases}

Now look for extrema along the boundary.

  • If x=-2, then

f(-2,y)=-y^3+12y-1\implies f'(-2,y)=-3y^2+12=0\implies y\pm2

We have f'(-2,y)>0 for -2 and f'(-2,y) for 2, which indicates a local maximum at y=2 and minima at the endpoints of this boundary. So

\begin{cases}f(-2,2)=15\\f(-2,-2)=-17\\f(-2,3)=8\end{cases}

  • If x=2, then

f(2,y)=y^3+12y+3\implies f'(2,y)=-3y^2+12=0\implies y=\pm2

We have f'(2,y) for 2, so we have extrema at the endpoints of this boundary.

\begin{cases}f(2,2)=19\\f(2,3)=12\end{cases}

  • If y=x, then

f(x,x)=9x+1\implies f'(x,x)=9>0

which tells us f is strictly increasing on this boundary, giving the extrema we already know about,

\begin{cases}f(-2,-2)=-17\\f(2,2)=19\end{cases}

  • If y=3, then

f(x,3)=x^3-3x+10\implies f'(x,3)=3x^2-3=0\implies x=\pm1

We have f'(x,3)>0 for -2 and 1, and f'(x,3) for -1. This indicates a maximum at x=-1 and a minimum at x=1, with

\begin{cases}f(-2,3)=8\\f(-1,3)=12\\f(1,3)=8\\f(2,3)=12\end{cases}

From this analysis, we find that f attains an absolute maximum of 19 at (-1, 2) and (2, 2), and an absolute minimum of -17 at (-2, -2).

4 0
3 years ago
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