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AURORKA [14]
3 years ago
10

5) A certain stock opens with a price of $0.59. Over the first three days the stock value increases at an average rate of 50% pe

r day. If this trend continues, how much will the stock be worth in 12 days?
Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

In 12 days the stock will be worth $ 76.55.

Step-by-step explanation:

Given that a certain stock opens with a price of $ 0.59, and over the first three days the stock value increases at an average rate of 50% per day, to determine, if this trend continues, how much will the stock be worth in 12 days the following calculation must be performed:

Initial value x rate of increase ^ number of years = X

0.59 x 1.5 ^ 12 = X

0.59 x 129.74 = X

76.55 = X

Therefore, in 12 days the stock will be worth $ 76.55.

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
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Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

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This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

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In this question:

y = -16x^2 + 177x + 98

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x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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