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AURORKA [14]
3 years ago
10

5) A certain stock opens with a price of $0.59. Over the first three days the stock value increases at an average rate of 50% pe

r day. If this trend continues, how much will the stock be worth in 12 days?
Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

In 12 days the stock will be worth $ 76.55.

Step-by-step explanation:

Given that a certain stock opens with a price of $ 0.59, and over the first three days the stock value increases at an average rate of 50% per day, to determine, if this trend continues, how much will the stock be worth in 12 days the following calculation must be performed:

Initial value x rate of increase ^ number of years = X

0.59 x 1.5 ^ 12 = X

0.59 x 129.74 = X

76.55 = X

Therefore, in 12 days the stock will be worth $ 76.55.

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36cm

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Consider the graph and equation, y = 3x, that represent Alonso’s walking speed. What relationship is represented by this equatio
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Answer:

The equation, y=3 x,

Step-by-step explanation:

y=Distance traveled

x =Total time

Also, in terms of straight line

Slope =3= uniform Velocity

Point (3,9) and (5,15) represents Distance traveled in 3 (unit of time) =9 unit, and 15 unit=Distance traveled in 5 (Unit of time).

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3 years ago
A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

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Answer:

$6

Step-by-step explanation:

let x and y be the number of chip and pretzel bags respectively  : 4x%2B2y%3 C=20 : if x=1 then 4%281%29%2B2y%3C=20--->{{2y<=16}}}--->y%3C=8  : if x=3 then 4%283%29%2B2y%3C=20--->{{2y<=8}}}--->y%3C=4  : so chips 1 and pretzels 8  : chips 3 and pretzels 4.

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