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3 years ago

What’s the mean Median Mode

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

3 0

Answer:

mean: 4.5 (1dp)

median: 4

mode: 6

Step-by-step explanation:

mean:

0 + 1 + 1 + 2 + 2 + 2 + 2 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 6 + 6 + 6 + 6 + 6 + 7 + 8 + 8 + 9 + 10 = 113

113 divided by 25 = 4.52, or just 4.5 (rounded to one decimal place

median:

(middle) = 4

mode:

(most occurring) = 6

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Given that W is directly proportional to the square of V, and W = 320 when V = 8, find W when V = 9.

lorasvet [3.4K]

The value of W when V = 9 is 405

<h3>How to solve for W?</h3>

The variation is a direct variation from W to V^2.

This means that:

W = kV^2

Where k is the constant of variation.

W = 320 when V = 8 means that:

320 = k * 8^2

Evaluate

320 = 64k

Divide both sides by 64

k = 5

Substitute k = 5 in W = kV^2

W = 5V^2

When V = 9, we have:

W = 5 * 9^2

Evaluate

W = 405

Hence, the value of W when V = 9 is 405

Read more about direct variation at:

brainly.com/question/6499629

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2 years ago

F(x) = 9-5x<br> For the function<br> 3+x<br> f-1(x).<br> find

Iteru [2.4K]

Answer:

f x − x + 3

Step-by-step explanation:

Substitute the given value into the function and evaluate.

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3 0

3 years ago

Simplify (2^3)^–2 ment to put this

aleksley [76]

Answer:

$\frac{1}{64}$

Step-by-step explanation:

$\left(2^3\right)^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(2^3\right)^{-2}=2^{3\left(-2\right)}\\\\3\left(-2\right)=-6\\=2^{-6}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\2^{-6}=\frac{1}{2^6}\\\\2^6=64\\\\=\frac{1}{64}$