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expeople1 [14]
3 years ago
5

What is the area of this shape?(look at picture)

Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0
The answer is B 21cm^2
Vesnalui [34]3 years ago
6 0
The answer is b 21cm2
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Ali spends 30% monthly income on food articles, 40% of the remaining on conveyance and clothes and saves 50% of the remaining. I
Romashka [77]

Ali saves Rs 2576 every month

Step-by-step explanation:

  • Step 1: Given Ali's monthly salary = Rs 18400. Calculate the amount spent on food articles

Amount spent on food = 30% of 18400 = 30/100 × 18400 = Rs 5520

  • Step 2: Find the remaining amount.

Remaining amount = 18400 - 5520 = Rs 12880

  • Step 3: Find amount spend on conveyance and clothes

Amount spent on conveyance and clothes = 40% of 12880

                              = 40/100 × 12880 = Rs 5152

  • Step 4: Find his monthly savings.

Monthly savings = 50% of 5152 = 50/100 × 5152 = Rs 2576

5 0
3 years ago
Read 2 more answers
An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
Given ∆QRS≅∆TUV, QS=4v+3, and TV=7v-9, find the length of QS and TV.?
Anon25 [30]
If we are supposed to assume that QS=TV

4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4

sub back

4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV

then answer is C
7 0
3 years ago
Read 2 more answers
Solve for u. 15u − 12u = 15
Leno4ka [110]

15u - 12u = 5

First combine like terms

3u = 5

Then isolate the variable by dividing both sides by 3

u = 5/3

u = 1 2/3

Hope this helped!

-TTL

6 0
3 years ago
Write 2,000,947 in word form and expanded form
pogonyaev
Word: Two Million Nine Hundred and Fourty Seven

5 0
3 years ago
Read 2 more answers
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