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boyakko [2]
3 years ago
13

Hey! please help posted picture of question

Mathematics
2 answers:
Ainat [17]3 years ago
7 0
The fraction shows 2/11 pieces were left.

This means, the birthday cake was divided into 11 pieces, 9 of them were eaten and 2 pieces were not eaten.

To ensure this we can add the fraction 2/11 (pieces left) and 9/11(pieces eaten). Since this results in 1 i.e. a whole cake, total pieces of the cake were 11

Thus the answer to this question is 2. 
lara31 [8.8K]3 years ago
3 0
The answer is D) 2

Since it is given that there have been 9 slices eaten, we can assume that whatever amount of slices were cut in total will have 9 reduced from the amount. With the fraction 2/11, we know 11-9=2, which fits perfectly into this description so 2 slices have not been eaten.
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you deposit 300 in an account that pays 5 1/2% annual interest compounded cnyinuously find the balance at the end of 5 years
algol [13]
First find the multiplier: 5.5% + 1 = 1.0505.

Then we do amount x (multiplier) to the power of how many years.

300 x (1.0505)^5

The answer is <span>383.79696707. 

We round this to 2dp, making it £393.80

REMEMBER UNITS!!!

Hope this helps xox :)</span>
7 0
3 years ago
Help me please,Thanks
maxonik [38]
<span>Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed in scientific notation?</span>
6 0
4 years ago
A firm has a beta of 1.3 and a debt-to-equity ratio of .4. The market rate of return is 11.6
Citrus2011 [14]

Beta= 1.3

Debt to equity ratio= 0.4

Market rate of return= 11.6%

= 11.6/100

= 0.116

Tax rate= 32%

= 32/100

= 0.32

Risk free rate=  3.3%

= 3.3/100

= 0.033

Pretax cost of debt= 7.2%

= 7.2/100

= 0.072

The firm's WACC can be calacluated as follows

RS= 0.033+1.3(0.116-0.033)

= 0.033+1.3(0.083)

= 0.033+0.1079

= 0.1409

WACC= (1/1.4)(0.1409)+(2/1.4) (0.072)(1-0.32)

= (0.7142)(0.1409) + (1.4285)(0.072)(0.68)

= 0.1006+0.0699

= 0.1705(100)

= 17.05%

Hence the firm's WACC is 17.05%

6 0
3 years ago
Dan earns $42.75 per month working as a tutor. He worked as a tutor for 4 months. He also earned $52.45 walking dogs in the neig
hjlf

Answer:

step 3

Step-by-step explanation:

in step 3, he wrote that the sum of 171+ 52.45-18.50 was 241.95 when it is 199.95

3 0
2 years ago
To increase the value of estimated Cohen's d, a researcher increases the sample size. Will this change the value of d?
tatyana61 [14]

Answer:

a. A) Yes; as sample size increases, effect size increases.

b. A) The critical value increases.

Step-by-step explanation:

a.

If all possible samples of size N are drawn from a finite population, Np, without replacement, and the standard deviation of the mean values of the sampling distribution of means is determined then:

σx =d  √N

d = σx . √N

d ∞ N

from this, we can say d is directly proportional to √N

where σx is the standard deviation of the sampling distribution of  means and d is the standard deviation of the population’. The standard deviation of a sampling distribution of mean values is called the standard error of the means,

therefore, we can conclude that:

A) Yes; as sample size increases, effect size increases.

b.

In this estimate, tc is called the confidence coefficient for small samples,  d is the standard deviation of the sample, x is the mean value of the sample and N is the number of members in the sample.

When determining the t-value, given by

t =( (x−µ) /s) * \sqrt{N-1}

it is necessary to know the sample parameters x and s and the population parameter µ. x and s can be calculated for the sample, but usually an estimate has to be made of the population mean µ, based on the sample mean value.

from the above equation it can be deduced that t value is determined with the sample size, and as the sample size increases

A) The critical value increases.

3 0
3 years ago
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