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nikitadnepr [17]
3 years ago
9

15.95=3.19n i need help with this

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

n=5

Step-by-step explanation:

EASY

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Question 4 (1 point)
mrs_skeptik [129]

Answer:

(C)y=0

Step-by-step explanation:

An exponential function of the form f(x) = a (b^x) + c always has a horizontal asymptote at y = c.

Given our function y=4^x

Comparing with the form,  f(x) = a (b^x) + c, we observe that c=0.

Therefore, the exponential function has an <u>asymptote at y=0.</u>

The correct option is C.

7 0
3 years ago
8x + y = 17<br> 5x + 5y = –20
Diano4ka-milaya [45]

Answer:

X=3 Y=-7

Step-by-step explanation:

You can solve a system of equations a number of ways. Substitution makes the most sense in this case. Take the top equation and set it equal to y making it: y=17-8x

Then substitute y in the bottom equation for the y solved in the top. So,

5x + 5(17-8x) = -20

Then solve for x

x=3

Now that we know x, plug it back into the equation for y

y = 17 - 8(3)

y = -7

So your solution is (3, -7)

8 0
3 years ago
Read 2 more answers
Please help! You will get 17 points!
lawyer [7]

Answer:

1695.6 is the volume.

Step-by-step explanation:

3.14 * 6^2 * 15 = 1695.6

8 0
3 years ago
Read 2 more answers
A 160-inch strip of metal 20 inches wide is to be made into a small open trough by bending up two sides on the long side, at rig
babymother [125]

Answer:

The value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

Step-by-step explanation:

The dimensions of given metal strip are

Length = 160 inch

Width = 20 inch

Let the side bend x inch from each sides to make a open box.

Dimensions of the box are

Length = 160-2x inch

Breadth = 20-2x inch

Height = x inch

The volume of a cuboid is

V=length\times breadth \times height

Volume of box is

V(x)=(160-2x)\times (20-2x)\times x

V(x)=(160-2x)(20-2x)x

V(x)=4 x^3 - 360 x^2 + 3200 x

Differentiate with respect to x.

V'(x)=12x^2 - 720 x + 3200

Equate V'(x)=0, to find the critical points.

0=12x^2 - 720 x + 3200

Using quadratic formula,

x=30\pm 10\sqrt{\frac{\left(19\right)}{3}}

The critical values are

x_1=30+10\sqrt{\frac{\left(19\right)}{3}}\approx 55.166

x_2=30-10\sqrt{\frac{\left(19\right)}{3}}\approx 4.834

Differentiate V'(x) with respect to x.

V'(x)=24x - 720

The value of double derivative at critical points are

V'(55.166)=24(55.166) - 720=603.984

V'(4.834)=24(4.834) - 720=-603.984

Since the value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

8 0
3 years ago
Read 2 more answers
Michael is watching a movie that is 2 1/3 hours long. If he has already watched 1 2/9 hours of the movie, how much of the movie
MrMuchimi

Answer:

1.1

Step-by-step explanation:

6 0
3 years ago
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