Set up the Pythagorean theorem.
The ladder is the hypotenuse
The wall is the length of the triangle
Pythagorean theorem states: a^2 + b^2 = c^2
Thus. 16^2 + b^2 = 12^2
Solve for b and that will be your answer for the question.
Answer:
y = 6/5x +2
Step-by-step explanation:
Slope intercept form is
y = mx+b where m is the slope and b is the y intercept
5y−6x−10=0
Add 10 to each side
5y−6x−10+10=0+10
5y -6x = 10
Add 6x to each side
5y-6x+6x=6x+10
5y = 6x+10
Divide each side by 5
5y/5 = 6x/5 +10/5
y = 6/5x +2
The slope is 6/5 and the y intercept is 2
A 10-foot ladder leans against a wall. It hits the wall 9 feet up. How far is the base of the ladder from the wall? Apply the Pythagorean Theorem to this problem
triangle
side S1 = 9 feet
hypotenuse H = 10 feet
side S2 - X = ?
the Pythagorean Theorem
H x H = S1 x S1 + S2 x S2 = S1 x S1 + X x X
X x X = H x H - S1 x S1 = 10 x 10 - 9 x 9 = 100 - 91 = 9
X x X = 9
X = 3
How far is the base of the ladder from the wall? 3 feet
check:
H x H = S1 x S1 + X x X
10 x 10 = 9 x 9 + 3 x 3
100 = 91 +9 = 100
It grows 33 cm per year
210 = the height of the tree when it was moved
33t = 33 cm per year (t)
Answer:
x=8
Step-by-step explanation:
xyz=256
x=y=2z
Replace y with x and z with x/2
x * (x) *(x/2) =256
x^3 /2 = 256
x^3 = 512
Take the cubed root of each side
(x^3) ^(1/3) = (512) ^ (1/3)
x=8