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3 years ago

WILL GIVE BRAINLINESS THING : Problem A painter is painting a mural on a wall. He has a 20-foot ladder. He needs to work on

1 answer:

7 0

Set up the Pythagorean theorem.

The ladder is the hypotenuse
The wall is the length of the triangle

Pythagorean theorem states: a^2 + b^2 = c^2

Thus. 16^2 + b^2 = 12^2

Solve for b and that will be your answer for the question.

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How do you make a function

dmitriy555 [2]

This site will tell you how https://sciencing.com/write-functions-math-8315770.html
I’m not very good at explaining it sorry

7 0

3 years ago

A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years. With all else equal, what is th

irga5000 [103]

Answer:

The future value of this initial investment after the six year period is $2611.6552

Step-by-step explanation:

Consider the provided information.

A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.

Future value of an investment: $FV=P(1+r)^n$

Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.

9% compounded semiannually for 6 years.

Therefore, the value of r is: $r=\frac{0.09}{2}=0.045$

Number of periods are: 2 × 6 = 12

Now substitute the respective values in the above formula.

$FV=1540(1+0.045)^{12}$

$FV=1540(1.045)^{12}$

$FV=1540(1.69588)$

$FV=2611.6552$

Hence, the future value of this initial investment after the six year period is $2611.6552

6 0

4 years ago

What is the smallest value in the stem and leaf plot below?

Alexeev081 [22]

Listing the data from the Stem and Leaves table as raw data we have:

02, 03, 03, 07, 10, 10, 17, 34, 34, 35, 35

Hence the smallest value is 02 = 2

Answer: A

7 0

3 years ago

What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?

DENIUS [597]

Answer:

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

a1 is first term

r is common ratio

We are given;

a1 = 156

r = ⅔

Thus;

S_∞ = 156/(1 - ⅔)

S_∞ = 156/(⅓)

S_∞ = 468

4 0

3 years ago

What is 2 with an exponent of negative 2 equal to?

balu736 [363]

Answer:

So since we have 2^-2 We can do 1/2^2 = 0.25

So if you have y^-x = 1/y^x

6 0

3 years ago

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