Question

Please help me! It’s due in few hours.

Answer 1

Lucky for me I just learned this lol
J: 3,6
K: stuck on this one because if you multiply one by 3/2 you get 3/2 so I don’t know
L:6,0


Able to get what I got, you have to multiply 3/2 by the the x and y axis. For example if x is “6” you’ll get 9. And so on.

Answer 2

Answer:

• J'(3, 6), K'(1.5, 1.5), L'(6, 0)

Step-by-step explanation:

△ JKL is dilated by 3/2

This transformation will result in the coordinates:

• (x, y) → (3/2x, 3/2y)

Apply the rule:

• J(2, 4) → J'(3/2*2 = 3, 3/2*4= 6) = (3, 6)
• K(1, 1) → K'(3/2*1 = 1.5, 3/2*1 = 1.5) = (1.5, 1.5)
• L(4, 0) → L'(3/2*4 = 6, 3/2*0 = 0) = (6, 0)