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Wewaii [24]
3 years ago
11

An​ alligator's tail​ length, T, varies directly as its body​ length, B. An alligator with a body length of 4.5 feet has a tail

length of 3.5 feet. What is the tail length of an alligator whose body length is 5.4 ​feet? decorative image
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0
If and only if it is a proportional relationship, the problem can be solved by creating a proportion of B1/T1=B2/T2. This can also be expressed as 4.5/3.5=5.4/x given the values. You must cross multiply, so 4.5x=3.5(5.4). This simplifies to x=4.2. So, the tail length would be 4.2 feet.

Hope this helps.
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Andrew [12]

The two events that created the most tension in the story include:

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  • Mr. White paid Sergeant-Major Morris a trifle for the paw.

<h3>What is tension?</h3>

It should be noted that tension in literature simply means the sense of something ominous in the literary work. It's a feeling that something is about to happen.

The Monkey's Paw is a horror short story by author W. W. Jacobs. In the story, three wishes are granted to the owner of The Monkey's Paw, but the wishes come with a price for interfering with fate.

It should be noted that Mrs. White suggesting that her husband wish for four hands for her created tension in the story as the readers were eager to know what happened in the story. Also, it should be noted Mr. White paying Sergeant-Major Morris a trifle for the paw created tension.

Learn more about tension on:

brainly.com/question/918617

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8 0
1 year ago
The x - coordinate of A' is _____<br> . The y - coordinate of A' is _____
Kazeer [188]

Answer:

(-3, 2)

Step-by-step explanation:

Since you are reflecting over the y-axis (the vertical axis), you are flipping the figure over to the left. As a result, you are going over to -3 and up to 2

8 0
3 years ago
Read 2 more answers
Can some one answer part B have to have it turned in by Monday ??????
Ira Lisetskai [31]

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6 0
3 years ago
What is 1/3 out of 100%
Andrej [43]
The answer your looking for is 33.3%

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5 0
4 years ago
If f(x) = 2x^4, then f'(3) =
valkas [14]

To find f'(3) (f prime of 3), you must find f' first.  f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is \frac{d}{dx} [x^{n} ] =nx^{n-1}.  In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = \frac{d}{dx}(2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

f'(3) = 216

<h3>Answer:</h3>

f'(3) = 216

6 0
3 years ago
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