Answer:
16 pies
Three-Quarters of 16 is 12, and if you sell 12, then you have a quarter which is 4, which ends up being every quarter which equaled 4
Answer:
x = 38, y = 4
Step-by-step explanation:
Since AB = BC then the triangle is isosceles and the base angles are congruent, that is
∠ DAB = ∠ DCB = 52°
Subtract the sum of the base angle from 180° for ∠ ABC
∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°
Note that ∠ ABD = ∠ CBD, thus
x = 76 ÷ 2 = 38
BD bisects the side AC, thus DC = AD = 4
Thus y = 4
Solution :
Given :

1. Cumulative distribution function




![$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D-%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cright%5D_6%5Ex%24)
![$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right] $](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%20%5Cleft%28%20%5Cfrac%7Bx%5E3%7D%7B3%7D%20-%20%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cleft%29%20-%20%5Cleft%28%20%5Cfrac%7B6%5E3%7D%7B3%7D%20-%20%5Cfrac%7B6%5E2%7D%7B2%7D%20%5Cright%29%20%5Cright%5D%20%20%24)
![$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%20-%20%5Cfrac%7Bx%5E2%7D%7B2%7D%20-%2054%20%5Cright%5D%24)
2. Mean 


![$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%20%5Cleft%5B%5Cfrac%7Bx%5E4%7D%7B4%7D%20-%20%5Cfrac%7Bx%5E3%7D%7B3%7D%20%5Cright%5D_6%5E%7B12%7D%20%5C%20dx%24)

![$=\frac{1}{450} [4608 - 252]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%20%5B4608%20-%20252%5D%24)
= 17.2857
Answer:
I think the total is 628.20$
Step-by-step explanation:
15*12=180
180*2.99=538.2
180*.5=90
90+538.2=628.2
Hope this helped :)